4/19/2023 0 Comments Error 0 vhdl logicworks![]() Neither condition in your two if statements require parenthesis. VHDL has fixed precedence with multiple operators of the same precedence. ![]() You could also note that the condition in an if statement is a boolean_expression (returns a boolean value), and expressions only require enclosing in matching left and right parenthesis to control association and evaluation order. Line 25 and 27 both assign a string value to std_logic type when the should assign an enumeration value (a character type). Line 18 makes the same mistake equality testing ck="1" while ck should also be the declared clock clk. String values are associated with string based types such as std_logic_vector, for example Line 17 `d<="000". areset is declared as std_logic, which uses enumeration values that are character literals. The first error on Line 16 occurs because there is no declared equality operator that compares between std_logic and string. Ghdl -a -ieee=synopsys -fexplicit acircuit.vhdlĪcircuit.vhdl:16:18: no function declarations for operator "="Īcircuit.vhdl:18:15: no declaration for "ck"Īcircuit.vhdl:25:12: can't match string literal "001" with type enumeration subtype "std_logic"Īcircuit.vhdl:27:12: can't match string literal "000" with type enumeration subtype "std_logic"ĥ port(a:in std_logic_vector(2 downto 0) ġ0 architecture ACircuitoComparatore of CircuitoComparatore isġ1 signal c,d: std_logic_vector(2 downto 0) ![]() Analyzing your design specification unchanged:
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